number systems Model Questions & Answers, Practice Test for ibps so prelims

Answer: (a)

Here 44 = 11 × 4

∴ the number must be divisible by 4 and 11 respectively.

Test of 4 says that 9y must be divisible by 4 and since y > 5, so y = 6

Again , x 9596 is divisible by 11

so x + 5 + 6 = 9 + 9 ⇒ x = 7

Thus x = 7, y = 6

Answer: (a)

The prime numbers less than 13 are 2, 3, 5, 7, 11.

Also, using the condition, p < q < r < 13 and p + q + r is a prime number

Hence, only two possible pairs exist i.e. (3, 5, 11) and (5, 7, 11).

Answer: (c)

Let the larger and smaller numbers be x and y respectively.

Then, x – y = 3 . ...(i)

and, $x^2 – y^2 = 63$

⇒ (x + y) (x – y) = 63

⇒ $(x + y) = 63/3 = 21$ ...(ii)

From equation (i) and (ii),

x = 12

Answer: (b)

∵ 5 chairs + 8 tables = Rs. 6574

∴ 10 chairs + 16 tables = 6574 × 2 = Rs.43148

Answer: (a)

Quicker Approach:

The unit's digit of the number 16128 is 8,

From the given answer choices, 126 × 128 = 16128

∴ Required larger number = 128